USACO Bronze 2016 December - The Cow-Signal

Authors: Benjamin Qi, Jesse Choe, Jeffery Meng

Official Analysis (Java)

Video Solution

By Jeffrey Meng

Video Solution Code

Implementation

Time Complexity: MNK2\mathcal{MN \cdot K^2}

C++

#include <bits/stdc++.h>
using namespace std;
void setIO(string name = "") {
ios_base::sync_with_stdio(0);
cin.tie(0);
if (name.size()) {
freopen((name + ".in").c_str(), "r", stdin);
freopen((name + ".out").c_str(), "w", stdout);
}

Java

import java.io.*;
import java.util.*;
public class CowSignal {
public static void main(String[] args) throws IOException {
BufferedReader read =
new BufferedReader(new FileReader("cowsignal.in"));
StringTokenizer initial = new StringTokenizer(read.readLine());
int height = Integer.parseInt(initial.nextToken());

Python

with open("cowsignal.in") as read:
height, width, scale = map(int, read.readline().split())
signal = [read.readline() for _ in range(height)]
with open("cowsignal.out", "w") as written:
for i in range(scale * height):
for j in range(scale * width):
print(signal[i // scale][j // scale], end="", file=written)
print(file=written)

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