Table of Contents

ExplanationImplementation

Official Analysis (C++)

Explanation

The simplest solution is to input three integers per row and check if their sum is greater than or equal to two.

Implementation

Time Complexity: O(N)\mathcal{O}(N)

C++

#include <iostream>
using namespace std;


int main() {
	int num = 0;
	int n;
	cin >> n;
	for (int i = 0; i < n; i++) {
		int a, b, c;
		cin >> a >> b >> c;
		if (a + b + c >= 2) { num++; }
	}
	cout << num << '\n';
}

Java

import java.io.*;
import java.util.*;
public class Team {
	public static void main(String[] args) {
		Kattio io = new Kattio();
		int num = 0;
		int n = io.nextInt();
		for (int i = 0; i < n; i++) {
			int a = io.nextInt();
			int b = io.nextInt();

Python

sols = 0
for _ in range(int(input())):
	sols += sum(int(i) for i in input().split()) >= 2
print(sols)

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